Concept:
When an ideal gas expands into an evacuated vessel at constant temperature, Boyle's law is applied:
\[
P_1V_1=P_2V_2
\]
Step 1: Initial pressure of gas is:
\[
P_1=760\text{ mm of Hg}
\]
Step 2: Initial volume of gas is:
\[
V_1=10\text{ L}
\]
Step 3: The gas is connected to an evacuated vessel of volume \(9\) L. Therefore, final volume becomes:
\[
V_2=10+9=19\text{ L}
\]
Step 4: Apply Boyle's law:
\[
P_1V_1=P_2V_2
\]
\[
760\times 10=P_2\times 19
\]
Step 5: Solve for \(P_2\):
\[
P_2=\frac{7600}{19}
\]
\[
P_2=400\text{ mm of Hg}
\]
\[
\boxed{400\text{ mm of Hg}}
\]