Question:

A vessel containing \(10\) liters of an ideal gas at a pressure of \(760\) mm of Hg is connected to an evacuated \(9\) liter vessel. The resultant pressure is

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When gas expands into an evacuated vessel, total final volume is the sum of both vessel volumes.
  • \(400\) mm of Hg
  • \(1440\) mm of Hg
  • \(40\) mm of Hg
  • \(760\) mm of Hg
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The Correct Option is A

Solution and Explanation

Concept:
When an ideal gas expands into an evacuated vessel at constant temperature, Boyle's law is applied: \[ P_1V_1=P_2V_2 \]

Step 1:
Initial pressure of gas is: \[ P_1=760\text{ mm of Hg} \]

Step 2:
Initial volume of gas is: \[ V_1=10\text{ L} \]

Step 3:
The gas is connected to an evacuated vessel of volume \(9\) L. Therefore, final volume becomes: \[ V_2=10+9=19\text{ L} \]

Step 4:
Apply Boyle's law: \[ P_1V_1=P_2V_2 \] \[ 760\times 10=P_2\times 19 \]

Step 5:
Solve for \(P_2\): \[ P_2=\frac{7600}{19} \] \[ P_2=400\text{ mm of Hg} \] \[ \boxed{400\text{ mm of Hg}} \]
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