Concept: Distance to horizon
For an observer at height $h$ above the Earth's surface, the distance to the horizon is:
\[
d = \sqrt{2Rh}
\]
where $R$ is the radius of the Earth.
Step 1: Geometrical idea
The line of sight to the horizon is tangential to the Earth.
This forms a right-angled triangle with:
- one side = $R$ (Earth’s radius)
- other side = $R + h$
Step 2: Apply Pythagoras
\[
(R + h)^2 = R^2 + d^2
\]
Step 3: Simplify
\[
R^2 + 2Rh + h^2 = R^2 + d^2
\]
\[
d^2 = 2Rh + h^2
\]
Step 4: Approximation
Since $h \ll R$, we neglect $h^2$:
\[
d \approx \sqrt{2Rh}
\]
Final Answer:
\[
\boxed{d = \sqrt{2Rh}}
\]
Conclusion:
Distance to horizon depends on both Earth's radius $R$ and observer height $h$.