Question

A. Total number of plants that can be accommodated in 6 ha of land with a spacing of 3X2 is approximately 100000
B. Total number of plants that can be accommodated in 6 ha of land with a spacing of 3X2 is approximately 10000
(Choose the correct answer from the options)

• A. A only
• B. B only
• C. C only
• D. D only

Hint:

Standard check: At \(2 \times 2\) spacing, you get 2,500 plants/ha. At \(3 \times 3\), you get ~1,111 plants/ha. For \(3 \times 2\) (6 sq.m), you get \(10000/6 \approx 1,666\) plants/ha. Multiplying by 6 ha gives exactly 10,000.

Answer 1

The Correct Option is B

Step 1: Understanding the Question:
The question asks to calculate the tree density (number of plants) per given area for a specified spacing.
Key Formula or Approach:
The formula for the number of plants (\(N\)) in a square or rectangular planting system is: \[ N = \frac{\text{Total Area}}{\text{Spacing (Row distance} \times \text{Plant distance)}} \] Note: \(1 \text{ hectare (ha)} = 10,000 \text{ square meters (sq.m)}\).

Step 2: Detailed Explanation:

• Area conversion: Total Area = 6 ha = \(6 \times 10,000 = 60,000 \text{ sq.m}\).

• Spacing calculation: Spacing = \(3 \text{ m} \times 2 \text{ m} = 6 \text{ sq.m per plant}\).

• Calculating Number of Plants: \[ N = \frac{60,000 \text{ sq.m}}{6 \text{ sq.m/plant}} \] \[ N = 10,000 \text{ plants} \]
• Comparing with Options: Statement B says approximately 10,000, which matches our calculation exactly. Statement A says 100,000, which is incorrect by a factor of 10.

Step 3: Final Answer:
The total number of plants for 6 ha at 3x2 spacing is 10,000. Thus, Statement B is correct.