Question:
A step down transformer connected to an a.c. mains of \(220\) V is made to operate at \(5.5\) V, \(44\) W lamp. The current in the primary circuit is (Ignore power losses)
A step down transformer connected to an a.c. mains of \(220\) V is made to operate at \(5.5\) V, \(44\) W lamp. The current in the primary circuit is (Ignore power losses)
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With no losses, input power equals the lamp power.
Updated On: Nov 12, 2026
- \(0.22\) A
- \(0.4\) A
- \(0.2\) A
- \(0.25\) A
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
For an ideal transformer, power drawn from the mains equals the output power: \(V_pI_p=44\) W.
Step 2: Calculation
\(I_p=\dfrac{44}{220}=0.2\) A.
Step 3: Check
Secondary current \(=\dfrac{44}{5.5}=8\) A, and \(\dfrac{I_p}{I_s}=\dfrac{5.5}{220}\) gives \(I_p=0.2\) A as well.
Final Answer:
The primary current is 0.2 A. \[ \boxed{\text{(C) }0.2\ \text{A}} \]
For an ideal transformer, power drawn from the mains equals the output power: \(V_pI_p=44\) W.
Step 2: Calculation
\(I_p=\dfrac{44}{220}=0.2\) A.
Step 3: Check
Secondary current \(=\dfrac{44}{5.5}=8\) A, and \(\dfrac{I_p}{I_s}=\dfrac{5.5}{220}\) gives \(I_p=0.2\) A as well.
Final Answer:
The primary current is 0.2 A. \[ \boxed{\text{(C) }0.2\ \text{A}} \]
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