Step 1: Understanding the Question:
We must identify which electrical parameter increases across the secondary coil in an ideal step-down transformer.
Step 2: Detailed Explanation:
Let's analyze the properties of an ideal transformer:
4.
Power: In an ideal transformer, there are no energy losses. Therefore, input power equals output power ($P_{\text{in}} = P_{\text{out}}$). Power remains constant.
5.
Frequency: A transformer operates on mutual induction and does not change the frequency of the alternating current. Frequency remains constant.
6.
Voltage: The very definition of a "step-down" transformer is one that reduces the voltage. Therefore, secondary voltage is lower than primary voltage ($V_s < V_p$).
7.
Current: Because power ($P = VI$) is conserved, a decrease in voltage must be perfectly compensated by a proportional increase in current.
$$V_p I_p = V_s I_s \implies \frac{V_p}{V_s} = \frac{I_s}{I_p}$$
Since $V_p > V_s$, it mathematically guarantees that $I_s > I_p$.
Step 3: Final Answer:
The quantity that increases is Current, matching option (C).