Question:
A spring is compressed between two toy carts of mass m₁ and m₂. When the toys are released, the springs exert equal and opposite average forces for the same time on each cart. If v₁ and v₂ are the velocities of the toy carts and there is no friction between the toy carts and the ground, then:
A spring is compressed between two toy carts of mass m₁ and m₂. When the toys are released, the springs exert equal and opposite average forces for the same time on each cart. If v₁ and v₂ are the velocities of the toy carts and there is no friction between the toy carts and the ground, then:
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In absence of external forces, momentum is conserved.
Updated On: Mar 18, 2026
- v₁ / v₂ = m₁ / m₂
- v₁ / v₂ = m₂ / m₁
- v₁ / v₂ = -m₁ / m₂
- v₁ / v₂ = -m₂ / m₁
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The Correct Option is D
Solution and Explanation
Step 1: Equal and opposite forces act for equal time.
Step 2: Hence impulses are equal and opposite: m₁ v₁ = - m₂ v₂
Step 3: Therefore, (v₁)/(v₂) = -(m₂)/(m₁)
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