Question:
A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is:
A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is:
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Impulse equals change in momentum.
Updated On: Mar 20, 2026
- \(MV\)
- \(1.5MV\)
- \(2MV\)
- zero
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The Correct Option is C
Solution and Explanation
Step 1: Initial momentum = MV.
Step 2: Final momentum = -MV.
Step 3: Impulse = Δ p = (-MV) - (MV) = -2MV.
Step 4: Magnitude of impulse = 2MV.
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