Question:

A spherically uniform planet of mass \( 8 \times 10^{24} \) kg and of radius \( 6 \times 10^6 \) m is orbiting around the Sun. The escape velocity for the planet is close to (Take \( G = 6 \times 10^{-11} \text{ N m}^2\text{kg}^{-2} \)) (A) 11.2 km/s

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Escape velocity depends only on \(M\) and \(R\).
Updated On: May 1, 2026
  • 16 km/s
  • 4 km/s
  • 12.6 km/s
  • 1.6 km/s
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The Correct Option is D

Solution and Explanation

Concept: Escape velocity
Escape velocity is the minimum speed required for an object to escape a planet’s gravitational field without further propulsion: \[ v = \sqrt{\frac{2GM}{R}} \]

Step 1: Substitute known values

For Earth: \[ G = 6.67 \times 10^{-11}, \quad M = 6 \times 10^{24} \text{ kg}, \quad R = 6.4 \times 10^6 \text{ m} \]

Step 2: Calculate

\[ v = \sqrt{\frac{2 \times 6.67 \times 10^{-11} \times 6 \times 10^{24}}{6.4 \times 10^6}} \] \[ v \approx 1.26 \times 10^4 \text{ m/s} \]

Step 3: Convert units

\[ v \approx 12.6 \text{ km/s} \] Final Answer:
\[ \boxed{12.6 \text{ km/s}} \] Note:
Escape velocity is independent of the mass of the object being projected.
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