Question:

A sounding source of frequency 500 Hz moves towards a stationary observer with a velocity 30 m/s. If the velocity of sound in air is 330 m/s find the frequency heard by the observer.

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A sounding source of frequency 500 Hz moves towards a stationary observer with a velocity 30 m/s. If the velocity of sound in air is 330 m/s find the frequency heard by the observer.
Updated On: Jun 21, 2026
  • 500 Hz
  • 550 Hz
  • 355 Hz
  • 55.5 Hz
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The Correct Option is B

Solution and Explanation

To solve this problem, we will use the concept of the Doppler Effect. The Doppler Effect describes the change in frequency (or wavelength) of a wave in relation to an observer moving relative to the wave source.

According to the Doppler Effect, the observed frequency (f') is given by the formula:

\(f' = \frac{c}{c-v_s} \cdot f\)

Where:

  • \(f'\) = observed frequency
  • \(f\) = source frequency (500 Hz)
  • \(c\) = velocity of sound in air (330 m/s)
  • \(v_s\) = velocity of the source moving towards the observer (30 m/s)

Substitute the given values into the formula:

\(f' = \frac{330}{330 - 30} \cdot 500\)

\(f' = \frac{330}{300} \cdot 500\)

\(f' = \frac{11}{10} \cdot 500\)

\(f' = 550 \text{ Hz}\)

Therefore, the frequency heard by the observer is 550 Hz.

The correct answer is 550 Hz, which matches the given correct answer.

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