Question:

A solid sphere of radius R has moment of inertia \(I\) about its diameter. What will be moment of inertia of a shell of same mass and same radius about its diameter?

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Remember standard results: solid sphere \( \frac{2}{5}MR^2 \), shell \( \frac{2}{3}MR^2 \).
Updated On: Apr 15, 2026
  • \( \frac{3}{5}I \)
  • \( \frac{5}{3}I \)
  • \( \frac{2}{3}I \)
  • \( \frac{2}{5}I \)
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The Correct Option is B

Solution and Explanation

Concept: Moment of inertia: \[ I_{\text{solid sphere}} = \frac{2}{5}MR^2 \] \[ I_{\text{shell}} = \frac{2}{3}MR^2 \]

Step 1:
Given relation.
\[ I = \frac{2}{5}MR^2 \Rightarrow MR^2 = \frac{5}{2}I \]

Step 2:
Shell moment of inertia.
\[ I_{\text{shell}} = \frac{2}{3}MR^2 = \frac{2}{3} \cdot \frac{5}{2}I = \frac{5}{3}I \]
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