Question:
A single effect evaporator concentrates 100 kg/hr fruit juice from 10% solids to 25% solids. The evaporation capacity in terms of water evaporated is:
A single effect evaporator concentrates 100 kg/hr fruit juice from 10% solids to 25% solids. The evaporation capacity in terms of water evaporated is:
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Material balance: Feed solids = Product solids.
Water evaporated = Feed - Product.
Water evaporated = Feed - Product.
Updated On: Aug 18, 2026
- 40 kg/hr
- 50 kg/hr
- 20 kg/hr
- 60 kg/hr
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Evaporation capacity is the amount of water removed.
Material balance is used to calculate it.
Step 2: Key Formula or Approach:
Solids balance: Feed solids = Product solids.
Water evaporated = Feed rate - Product rate.
Step 3: Detailed Explanation:
Feed = 100 kg/hr, solids = 10% = 10 kg solids.
Product solids = 25%, so product rate = 10 0.25 = 40 kg/hr.
Water evaporated = 100 - 40 = 60 kg/hr.
Thus, the evaporation capacity is 60 kg/hr.
Step 4: Final Answer:
The evaporation capacity is 60 kg/hr.
Hence, the correct option is (D).
Evaporation capacity is the amount of water removed.
Material balance is used to calculate it.
Step 2: Key Formula or Approach:
Solids balance: Feed solids = Product solids.
Water evaporated = Feed rate - Product rate.
Step 3: Detailed Explanation:
Feed = 100 kg/hr, solids = 10% = 10 kg solids.
Product solids = 25%, so product rate = 10 0.25 = 40 kg/hr.
Water evaporated = 100 - 40 = 60 kg/hr.
Thus, the evaporation capacity is 60 kg/hr.
Step 4: Final Answer:
The evaporation capacity is 60 kg/hr.
Hence, the correct option is (D).
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