Question:
A police jeep is chasing with velocity of 45 km/h a thief in another jeep moving with velocity 153 km/h. Police fires a bullet with muzzle velocity of 180 m/s. The velocity with which it will strike the car of the thief is
A police jeep is chasing with velocity of 45 km/h a thief in another jeep moving with velocity 153 km/h. Police fires a bullet with muzzle velocity of 180 m/s. The velocity with which it will strike the car of the thief is
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Always convert km/h to m/s by multiplying by \(\frac{5}{18}\).
Updated On: Apr 23, 2026
- 150 m/s
- 27 m/s
- 450 m/s
- 250 m/s
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Relative velocity = velocity of bullet relative to ground minus velocity of thief.
Step 2: Detailed Explanation:
Police speed = 45 km/h = \(45 \times \frac{5}{18} = 12.5\) m/s.
Thief speed = 153 km/h = \(153 \times \frac{5}{18} = 42.5\) m/s.
Muzzle velocity is relative to police jeep. Bullet velocity relative to ground = \(180 + 12.5 = 192.5\) m/s (same direction).
Relative velocity of bullet wrt thief = \(192.5 - 42.5 = 150\) m/s.
Step 3: Final Answer:
Thus, striking velocity = 150 m/s.
Relative velocity = velocity of bullet relative to ground minus velocity of thief.
Step 2: Detailed Explanation:
Police speed = 45 km/h = \(45 \times \frac{5}{18} = 12.5\) m/s.
Thief speed = 153 km/h = \(153 \times \frac{5}{18} = 42.5\) m/s.
Muzzle velocity is relative to police jeep. Bullet velocity relative to ground = \(180 + 12.5 = 192.5\) m/s (same direction).
Relative velocity of bullet wrt thief = \(192.5 - 42.5 = 150\) m/s.
Step 3: Final Answer:
Thus, striking velocity = 150 m/s.
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