Question:
A particle moving with an initial velocity of $1\ \text{m s}^{-1}$ has a uniform acceleration of $2\ \text{m s}^{-2}$. The distances travelled by the particle in the first two intervals of $5\ \text{s}$ are respectively:
A particle moving with an initial velocity of $1\ \text{m s}^{-1}$ has a uniform acceleration of $2\ \text{m s}^{-2}$. The distances travelled by the particle in the first two intervals of $5\ \text{s}$ are respectively:
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To find the distance in the "next" interval, subtract the total distance of the previous intervals from the new total distance.
Updated On: Apr 28, 2026
- 30 m and 110 m
- 50 m and 110 m
- 40 m and 80 m
- 30 m and 80 m
- 60 m and 160 m
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Use the kinematic equation $s = ut + \frac{1}{2}at^2$.
Step 2: Calculation (First 5 s)
$s_1 = (1)(5) + \frac{1}{2}(2)(5)^2 = 5 + 25 = 30\ m$.
Step 3: Calculation (Next 5 s)
Total distance in 10 s: $s_{10} = (1)(10) + \frac{1}{2}(2)(10)^2 = 10 + 100 = 110\ m$. Distance in second interval $= s_{10} - s_1 = 110 - 30 = 80\ m$. Final Answer: (D)
Use the kinematic equation $s = ut + \frac{1}{2}at^2$.
Step 2: Calculation (First 5 s)
$s_1 = (1)(5) + \frac{1}{2}(2)(5)^2 = 5 + 25 = 30\ m$.
Step 3: Calculation (Next 5 s)
Total distance in 10 s: $s_{10} = (1)(10) + \frac{1}{2}(2)(10)^2 = 10 + 100 = 110\ m$. Distance in second interval $= s_{10} - s_1 = 110 - 30 = 80\ m$. Final Answer: (D)
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