Question:

A p-n junction diode \((D)\) shown in the figure below can act as a rectifier. An alternating current source \((V)\) is connected in the circuit. The current \((I)\) in the resistor \((R)\) can be shown by which graph?

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A single diode produces a half-wave rectified output: \[ \text{Positive half-cycle} \rightarrow \text{Current flows} \] \[ \text{Negative half-cycle} \rightarrow \text{No current} \] A full-wave rectifier requires two diodes with a centre-tapped transformer or four diodes in a bridge rectifier.
Updated On: Jun 11, 2026
  • Graph 1
  • Graph 2
  • Graph 3
  • Graph 4
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The Correct Option is B

Solution and Explanation

Concept: A single p-n junction diode in series with a resistor acts as a half-wave rectifier.
• During the positive half-cycle, the diode is forward biased and current flows.
• During the negative half-cycle, the diode is reverse biased and current does not flow. Therefore, only one half of the AC signal appears across the load resistor.

Step 1:
Analyse the positive half-cycle. When the input voltage is positive, \[ \text{Diode is forward biased} \] Hence, \[ I \neq 0 \] and current flows through the resistor.

Step 2:
Analyse the negative half-cycle. When the input voltage is negative, \[ \text{Diode is reverse biased} \] Hence, \[ I=0 \] and no current flows through the resistor.

Step 3:
Identify the output waveform. The output current consists of only positive half-cycles separated by intervals of zero current. This corresponds to a half-wave rectified output. \[ \boxed{ \text{Current flows only during alternate half-cycles.} } \]

Step 4:
State the answer. The correct graph is \[ \boxed{\text{Graph 2}} \] Hence, the correct option is \[ \boxed{(B)} \]
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