Question:
A moving coil galvanometer of coil resistance 12 ohms shows full scale deflection for a current of 3 mA. It can be converted into a voltmeter of range 0-18 V by connecting
A moving coil galvanometer of coil resistance 12 ohms shows full scale deflection for a current of 3 mA. It can be converted into a voltmeter of range 0-18 V by connecting
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V for Voltmeter \(\rightarrow\) S for Series (High R).
A for Ammeter \(\rightarrow\) P for Parallel (Low R).
This mnemonic helps you remember the correct configuration for conversion.
A for Ammeter \(\rightarrow\) P for Parallel (Low R).
This mnemonic helps you remember the correct configuration for conversion.
Updated On: Jun 24, 2026
- 0.01 ohms in series with the galvanometer
- 5988 ohms in parallel with the galvanometer
- 0.01 ohms in parallel with the galvanometer
- 5988 ohms in series with the galvanometer
- 6200 ohms in series with the galvanometer
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
To convert a galvanometer into a voltmeter, a high resistance (shunt) must be connected in series with the galvanometer. This ensures that most of the voltage drop occurs across the added resistance.
Step 2: Key Formula or Approach:
Series resistance required: \(R = \frac{V}{I_g} - G\)
Step 3: Detailed Explanation:
Given:
\(G = 12 \Omega\)
\(I_g = 3 \text{ mA} = 3 \times 10^{-3} \text{ A}\)
Desired range \(V = 18 \text{ V}\)
Calculation:
\[ R = \frac{18}{3 \times 10^{-3}} - 12 \]
\[ R = \frac{18000}{3} - 12 \]
\[ R = 6000 - 12 = 5988 \Omega \]
This resistance must be connected in series.
Step 4: Final Answer:
Connect 5988 ohms in series with the galvanometer.
To convert a galvanometer into a voltmeter, a high resistance (shunt) must be connected in series with the galvanometer. This ensures that most of the voltage drop occurs across the added resistance.
Step 2: Key Formula or Approach:
Series resistance required: \(R = \frac{V}{I_g} - G\)
Step 3: Detailed Explanation:
Given:
\(G = 12 \Omega\)
\(I_g = 3 \text{ mA} = 3 \times 10^{-3} \text{ A}\)
Desired range \(V = 18 \text{ V}\)
Calculation:
\[ R = \frac{18}{3 \times 10^{-3}} - 12 \]
\[ R = \frac{18000}{3} - 12 \]
\[ R = 6000 - 12 = 5988 \Omega \]
This resistance must be connected in series.
Step 4: Final Answer:
Connect 5988 ohms in series with the galvanometer.
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