Question:

A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per mA and Voltage sensitivity is 2 divisions per millivolt. In order to read each division 1 volt, the resistance in ohms to be connected in series is:

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To turn a galvanometer into a voltmeter, add a large resistance in series.
Updated On: Jun 6, 2026
  • 9995
  • 995
  • 95
  • 99995
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The Correct Option is A

Solution and Explanation

Step 1: Concept
Conversion of a galvanometer into a voltmeter.

Step 2: Meaning
Total resistance required $R = (V/I_g) - G$, where $G$ is the galvanometer resistance.

Step 3: Analysis
Current sensitivity $= 10$ div/mA $\rightarrow I_{div} = 10^{-4}$ A/div. Voltage sensitivity $= 2$ div/mV $\rightarrow V_{div} = 0.5 \times 10^{-3}$ V/div. Galvanometer resistance $G = V_{div} / I_{div} = (0.5 \times 10^{-3}) / 10^{-4} = 5~\Omega$. For 150 divisions to read 150 Volts (each div 1 V), $V = 150$ V. Current for full scale $I_g = 150 \times 10^{-4} = 0.015$ A. $R + G = V/I_g = 150 / 0.015 = 10000~\Omega$. $R = 10000 - 5 = 9995~\Omega$.

Step 4: Conclusion
The required series resistance is 9995 $\Omega$.

Final Answer: (A)
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