Question:
A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is
A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is
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For a polyatomic gas with \(f\) degrees of freedom, \(C_p = (\frac{f}{2} + 1)R\).
Updated On: May 6, 2026
- \(\frac{R}{2}\)
- \(R\)
- \(\frac{3R}{2}\)
- \(2R\)
- \(3R\)
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The Correct Option is
Solution and Explanation
Concept:
Molar specific heat at constant volume (\(C_v\)) is related to degrees of freedom (\(f\)) by:
\[ C_v = \frac{f}{2}R \]
Step 1: Calculation.
For \(f = 6\): \[ C_v = \frac{6}{2}R = 3R \]
Step 1: Calculation.
For \(f = 6\): \[ C_v = \frac{6}{2}R = 3R \]
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