Question

A man of mass $60$ kg climbed down using an elevator. The elevator had an acceleration $4$ m/s$^2$. If the acceleration due to gravity is $10$ m/s$^2$, the apparent weight on his way down is

• A. $60$ N
• B. $240$ N
• C. $360$ N
• D. $840$ N
• E. $3600$ N

Hint:

If elevator accelerates downward, apparent weight decreases: $N = m(g-a)$.

Answer 1

The Correct Option is C

Concept:
Apparent weight when moving downward: \[ N = m(g - a) \]

Step 1: Substitute values.
\[ m = 60,\quad g = 10,\quad a = 4 \] \[ N = 60(10 - 4) \]

Step 2: Calculate.
\[ N = 60 \times 6 = 360 \text{ N} \]