Step 1: Understanding the Concept:
Time of flight for one ball: \(T = \frac{2u}{g} = \frac{2\times20}{10} = 4 \text{ s}\). Balls are thrown at regular intervals of 1 second.
Step 2: Detailed Explanation:
At \(t=0\), one ball is thrown; previous balls have been in air for 1 s, 2 s, and 3 s. Height formula: \(h = ut - \frac{1}{2}gt^2\). For \(t=1\): \(h = 20\times1 - 5\times1 = 15 \text{ m}\). For \(t=2\): \(h = 40 - 20 = 20 \text{ m}\). For \(t=3\): \(h = 60 - 45 = 15 \text{ m}\). Heights are: 15 m, 20 m, 15 m.
Step 3: Final Answer:
\[
\boxed{15,\; 20,\; 15}
\]