Question

A flow of \(10^6\) electrons per second in a conducting wire constitutes a flow of current of

• A. \(1.6 \times 10^{-15}A\)
• B. \(1.6 \times 10^{-11}A\)
• C. \(1.6 \times 10^{-12}A\)
• D. \(1.6 \times 10^{-19}A\)
• E. \(1.6 \times 10^{-13}A\)

Hint:

Current = charge flow per second → multiply number of electrons with charge.

Answer 1

Answer: (E)

Concept: Current: \[ I = nq \] where \(n\) = number of charges per second, \(q\) = charge of electron.

Step 1: Given values. \[ n = 10^6 \text{ electrons/s}, \quad q = 1.6 \times 10^{-19}C \]

Step 2: Substitute. \[ I = 10^6 \times 1.6 \times 10^{-19} \]

Step 3: Simplify powers. \[ I = 1.6 \times 10^{-13}A \]

Step 4: Conclusion. \[ \boxed{1.6 \times 10^{-13}A} \]