Question:
A current of 4 A is flowing at 230 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2300 V and 40 % of power is lost, then the current in the secondary will be
A current of 4 A is flowing at 230 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2300 V and 40 % of power is lost, then the current in the secondary will be
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Output power is 60 percent of input power, then divide by the secondary voltage.
Updated On: Oct 1, 2026
- \(0.24\) A
- \(0.2\) A
- \(0.12\) A
- \(0.4\) A
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Power lost means the output power is smaller than the input power. Here 40% is lost, so 60% is delivered.
Step 2: Input power
\[ P_{in}=V_pI_p=230\times4=920\ \text{W} \]
Step 3: Output power
\[ P_{out}=0.60\times920=552\ \text{W} \]
Step 4: Secondary current
\[ I_s=\frac{P_{out}}{V_s}=\frac{552}{2300}=0.24\ \text{A} \]
Step 5: Check the options
An ideal transformer would give \(920/2300=0.4\) A, which is option (D). With the 40% loss it is smaller. So 0.24 A, option (A).
Final Answer:
The output power is 552 W at 2300 V, so the secondary current is 0.24 A, option (A). \[ \boxed{0.24\ \text{A}} \]
Power lost means the output power is smaller than the input power. Here 40% is lost, so 60% is delivered.
Step 2: Input power
\[ P_{in}=V_pI_p=230\times4=920\ \text{W} \]
Step 3: Output power
\[ P_{out}=0.60\times920=552\ \text{W} \]
Step 4: Secondary current
\[ I_s=\frac{P_{out}}{V_s}=\frac{552}{2300}=0.24\ \text{A} \]
Step 5: Check the options
An ideal transformer would give \(920/2300=0.4\) A, which is option (D). With the 40% loss it is smaller. So 0.24 A, option (A).
Final Answer:
The output power is 552 W at 2300 V, so the secondary current is 0.24 A, option (A). \[ \boxed{0.24\ \text{A}} \]
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