Question:

A current carrying coil is bent sharply so as to convert it into a double loop both carrying current in the same direction. If B be the initial magnetic field at the centre, then what will be the final concentric magnetic field?

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When a loop is folded, radius reduces and field increases.
Updated On: Apr 16, 2026
  • 2 B
  • 4 B
  • 8 B
  • Zero
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The Correct Option is B

Solution and Explanation


Step 1:
For a circular loop, $B = \frac\mu₀ I2r$.

Step 2:
When bent into double loop, each loop has radius $r/2$. Field due to each: $B' = \frac\mu₀ I2(r/2) = \frac\mu₀ Ir$. Two loops: $Btotal = 2 × \frac\mu₀ Ir = 4B$.
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