A current carrying coil is bent sharply so as to convert it into a double loop both carrying current in the same direction. If B be the initial magnetic field at the centre, then what will be the final concentric magnetic field?
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When a loop is folded, radius reduces and field increases.
Step 1: For a circular loop, $B = \frac\mu₀ I2r$. Step 2: When bent into double loop, each loop has radius $r/2$. Field due to each: $B' = \frac\mu₀ I2(r/2) = \frac\mu₀ Ir$. Two loops: $Btotal = 2 × \frac\mu₀ Ir = 4B$.