Question:

A cubical block of side \(0.5\ \mathrm{m}\) floats on water with \(30\%\) of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water? [Take, density of water \(=10^{3}\ \mathrm{kg/m^3}\)]

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At the limit the block is fully submerged, so the extra load equals the extra buoyant force.
Updated On: Nov 5, 2026
  • \(30.1\ \mathrm{kg}\)
  • \(87.5\ \mathrm{kg}\)
  • \(65.4\ \mathrm{kg}\)
  • \(46.3\ \mathrm{kg}\)
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The Correct Option is B

Solution and Explanation

Volume \(V=0.5^3=0.125\ \mathrm{m^3}\).
Floating with 30% submerged: \(m_{block}g=0.3V\rho g\Rightarrow m_{block}=0.3\times0.125\times10^{3}=37.5\ \mathrm{kg}\).
Just fully submerged: \((m_{block}+m)g=V\rho g\Rightarrow m_{block}+m=125\ \mathrm{kg}\).
\(m=125-37.5=87.5\ \mathrm{kg}\).
Answer: (2) 87.5 kg
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