
Analyze Statement I:
Statement I states that when the speed of liquid is zero everywhere, the pressure difference at any two points depends on the equation:
\[ P_1 - P_2 = \rho g(h_2 - h_1) \]
This is correct and is based on the hydrostatic pressure difference, which applies when the fluid is at rest or moving uniformly without velocity gradients.
Analyze Statement II Using Bernoulli’s Equation:
In a venturi tube, where the fluid is in motion, we can apply Bernoulli’s equation:
\[ P_1 + \rho gh + \frac{1}{2}\rho v_1^2 = P_2 + \rho gh + \frac{1}{2}\rho v_2^2 \]
Simplifying for the pressure difference, we get:
\[ P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2) \]
The statement given, \(2gh = v_2^2 - v_1^2\), is not a general result of Bernoulli’s equation and is incorrect as presented.
Conclusion:
Therefore, Statement I is correct (it applies to a static fluid or uniform motion with no speed variations), but Statement II is incorrect in the context of the venturi tube.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)