Question:
A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?
A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?
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A convex lens is placed between object and a screen. The size of object is 3 cm and an image of height 9 cm is obtained on the screen. When the lens is displaced to a new position, what will be the size of image on the screen?
Updated On: Apr 15, 2026
- 2 cm
- 6 cm
- 4 cm
- 1 cm
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The Correct Option is D
Solution and Explanation
Step 1: Concept
In the displacement method, size of object $O = \sqrt{I_{1}I_{2}}$.
Step 2: Substitution
$O = 3 \text{ cm}, I_{1} = 9 \text{ cm}$. $3 = \sqrt{9 \times I_{2}}$.
Step 3: Calculation
$9 = 9 \times I_{2} \Rightarrow I_{2} = 1 \text{ cm}$.
Final Answer: (D)
In the displacement method, size of object $O = \sqrt{I_{1}I_{2}}$.
Step 2: Substitution
$O = 3 \text{ cm}, I_{1} = 9 \text{ cm}$. $3 = \sqrt{9 \times I_{2}}$.
Step 3: Calculation
$9 = 9 \times I_{2} \Rightarrow I_{2} = 1 \text{ cm}$.
Final Answer: (D)
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