Question:
A constant torque acting on a uniform circular wheel changes its angular momentum from $A₀$ to $4A₀$ in 4s. The magnitude of this torque is
A constant torque acting on a uniform circular wheel changes its angular momentum from $A₀$ to $4A₀$ in 4s. The magnitude of this torque is
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A constant torque acting on a uniform circular wheel changes its angular momentum from $A0$ to $4A0$ in 4s. The magnitude of this torque is
Updated On: Apr 15, 2026
- $\frac{3A_{0}}{4}$
- $A_{0}$
- $4A_{0}$
- $12A_{0}$
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The Correct Option is A
Solution and Explanation
Step 1: Formula
Torque $\tau = \frac{dL}{dt}$ (Rate of change of angular momentum).
Step 2: Values
$L_{1} = A_{0}, L_{2} = 4A_{0}, \Delta t = 4 \text{ s}$.
Step 3: Calculation
$\tau = \frac{4A_{0} - A_{0}}{4} = \frac{3A_{0}}{4}$.
Final Answer: (A)
Torque $\tau = \frac{dL}{dt}$ (Rate of change of angular momentum).
Step 2: Values
$L_{1} = A_{0}, L_{2} = 4A_{0}, \Delta t = 4 \text{ s}$.
Step 3: Calculation
$\tau = \frac{4A_{0} - A_{0}}{4} = \frac{3A_{0}}{4}$.
Final Answer: (A)
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