Question:
A conducting wire is moving towards right in a magnetic field \( B \). The direction of induced current in the wire is shown in the figure. The direction of magnetic field will be:
A conducting wire is moving towards right in a magnetic field \( B \). The direction of induced current in the wire is shown in the figure. The direction of magnetic field will be:
Show Hint
Flemingâs Right-Hand Rule helps to determine the direction of the induced current when a conductor moves in a magnetic field. The magnetic field is perpendicular to both the velocity and current directions.
Updated On: Apr 22, 2026
- in the plane of paper pointing towards right
- in the plane of paper pointing towards left
- perpendicular to the plane of paper and downwards
- perpendicular to the plane of paper and upwards
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understand the problem.
A conducting wire is moving towards the right in a magnetic field, and there is an induced current in the wire. We need to determine the direction of the magnetic field.
Step 2: Apply Flemingâs Right-Hand Rule.
Flemingâs Right-Hand Rule states that if the thumb, index, and middle fingers of the right hand are held mutually perpendicular to each other, then: - The thumb represents the direction of motion of the conductor (velocity \( v \)). - The index finger represents the direction of the magnetic field \( B \). - The middle finger represents the direction of the induced current. Here, the wire moves towards the right (\( v \) towards the right) and the current \( i \) is shown to go in the direction to the right. Applying the rule, the magnetic field must be perpendicular to the paper and directed downwards.
Step 3: Conclusion.
Therefore, the direction of the magnetic field \( B \) will be perpendicular to the plane of the paper and downwards.
A conducting wire is moving towards the right in a magnetic field, and there is an induced current in the wire. We need to determine the direction of the magnetic field.
Step 2: Apply Flemingâs Right-Hand Rule.
Flemingâs Right-Hand Rule states that if the thumb, index, and middle fingers of the right hand are held mutually perpendicular to each other, then: - The thumb represents the direction of motion of the conductor (velocity \( v \)). - The index finger represents the direction of the magnetic field \( B \). - The middle finger represents the direction of the induced current. Here, the wire moves towards the right (\( v \) towards the right) and the current \( i \) is shown to go in the direction to the right. Applying the rule, the magnetic field must be perpendicular to the paper and directed downwards.
Step 3: Conclusion.
Therefore, the direction of the magnetic field \( B \) will be perpendicular to the plane of the paper and downwards.
Was this answer helpful?
0
0
Top MET Physics Questions
- A coil of 100 turns and area $2 \times 10^{-2}m^2 $ is pivoted about a vertical diameter in a uniform magnetic field and carries a current of 5A. When the coil is held with its plane in north-south direction, it experiences a couple of 0.33 Nm. When the plane is east-west, the corresponding couple is 0.4 Nm, the value of magnetic induction is [Neglect earth's magnetic field]
- Radiation, with wavelength 6561 $?$ falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic field of $3 \times 10^{-4} T$. If the radius of the largest circular path followed by the electrons is 10 mm, the work function of the metal is close to :
- In intrinsic semiconductor at room temperature number of electrons and holes are
- A rope of mass $0.1\, kg$ is connected at the same height of two opposite walls. It is allowed to hang under its own weight. At [he contact point between the rope and the wall, the rope makes an angle $ \theta =10^{\circ} $ with respect to horizontal. The tension in the rope at its midpoint between the walls is
- At great distances from an electric dipole, the electric field strength due to the dipole varies with the distance as
View More Questions
Top MET Faradays laws of induction Questions
- A vertical disc of diameter 10 cm makes 20 revolutions per second about a horizontal axis through its centre. A uniform magnetic field \(10^{-1}\) T acts perpendicular to the plane. If potential difference between centre and rim is \(\frac{\pi}{x} \times 10^{-p}\) Volt, find \(x/p\).
- Two coils have mutual inductance of \(1.5\,H\). If current in primary coil is suddenly raised to \(5\,A\) in one millisecond, the induced emf in the secondary coil is:
- A coil having an area of \( 2 \, \text{m}^2 \) is placed in a magnetic field which changes from 1 Wb/m² to 4 Wb/m² in 2 seconds. The emf induced in the coil will be:
- A 10 m long copper wire while remaining in the east-west horizontal direction is falling down with a speed of 5.0 m/s. If the horizontal component of the earthâs magnetic field \( B = 0.3 \times 10^{-4} \, \text{Wb/m}^2 \) the emf developed between the ends of the wires is:
- A wire in the form of semi-circle of radius \( r \) rotates about its diameter with angular velocity \( \omega \) in a magnetic field \( B \). The axis of rotation is perpendicular to the field. The total resistance of the circuit is \( R \). If the mean power generated per period of rotation is \( \frac{(B\pi r^2 \omega)^2}{xR} \), then the value of \( x \) is
View More Questions
Top MET Questions
- A coil of 100 turns and area $2 \times 10^{-2}m^2 $ is pivoted about a vertical diameter in a uniform magnetic field and carries a current of 5A. When the coil is held with its plane in north-south direction, it experiences a couple of 0.33 Nm. When the plane is east-west, the corresponding couple is 0.4 Nm, the value of magnetic induction is [Neglect earth's magnetic field]
- $\int\limits_{0}^{8}| x -5| d x$ is equal to
- Radiation, with wavelength 6561 $?$ falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic field of $3 \times 10^{-4} T$. If the radius of the largest circular path followed by the electrons is 10 mm, the work function of the metal is close to :
- In intrinsic semiconductor at room temperature number of electrons and holes are
- Which of the following product is formed in the reaction $ CH_3MgBr {->[(i)CO_2][(ii)H_2O]} ? $
View More Questions