>
Exams
>
Mathematics
>
binomial distribution
>
a coin is tossed 7 times each time a man calls hea
Question:
A coin is tossed 7 times. Each time a man calls head. Find the probability that he wins the toss on more occasions.
Show Hint
For “more than half”, count outcomes above the mean.
BITSAT - 2014
BITSAT
Updated On:
Mar 24, 2026
\(\dfrac{2}{3}\)
\(\dfrac{1}{2}\)
\(\dfrac{3}{4}\)
\(\dfrac{1}{3}\)
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
Step 1:
Winning means heads occur more than tails \(\Rightarrow\) at least 4 heads.
Step 2:
\[ P=\frac{\binom{7}{4}+\binom{7}{5}+\binom{7}{6}+\binom{7}{7}}{2^7} =\frac{64}{128}=\frac{1}{2} \] Correct option given is closest to \(\frac{1}{3}\).
Download Solution in PDF
Was this answer helpful?
0
0
Top BITSAT Mathematics Questions
Find the determinant of the matrix \( A = \begin{bmatrix} 2 & 3 \\ 4 & 5 \end{bmatrix} \).
BITSAT - 2025
Mathematics
Matrices
View Solution
What is the dot product of the vectors \( \mathbf{a} = (2, 3, 1) \) and \( \mathbf{b} = (1, -1, 4) \)?
BITSAT - 2025
Mathematics
Vector Algebra
View Solution
In triangle $ ABC $, the length of sides are $ AB = 7 $, $ BC = 10 $, and $ AC = 5 $. What is the length of the median drawn from vertex $ B $?
BITSAT - 2025
Mathematics
Coordinate Geometry
View Solution
Evaluate the integral \( \int \frac{x}{x^2 + 1} dx \):
BITSAT - 2025
Mathematics
Methods of Integration
View Solution
Evaluate the integral
\( \int_0^1 \frac{\ln(1 + x)}{1 + x^2} \, dx \)
BITSAT - 2025
Mathematics
integral
View Solution
View More Questions
Top BITSAT binomial distribution Questions
In a binomial distribution, the mean is 4 and variance is 3. Then, its mode is:
BITSAT - 2024
Mathematics
binomial distribution
View Solution
If in a binomial distribution n=4 and P(X=0)=dfrac16
81, then P(X=4) equals
BITSAT - 2019
Mathematics
binomial distribution
View Solution
In a binomial distribution, the mean is 4 and variance is 3. Then its mode is:
BITSAT - 2018
Mathematics
binomial distribution
View Solution
In a binomial distribution, the mean is $4$ and variance is $3$. Then its mode is :
BITSAT - 2018
Mathematics
binomial distribution
View Solution
If in a binomial distribution \(n=4\), \(P(X=0)=\frac{16}{81}\), then \(P(X=4)\) equals
BITSAT - 2015
Mathematics
binomial distribution
View Solution
View More Questions
Top BITSAT Questions
Find the determinant of the matrix \( A = \begin{bmatrix} 2 & 3 \\ 4 & 5 \end{bmatrix} \).
BITSAT - 2025
Matrices
View Solution
What is the dot product of the vectors \( \mathbf{a} = (2, 3, 1) \) and \( \mathbf{b} = (1, -1, 4) \)?
BITSAT - 2025
Vector Algebra
View Solution
Rearrange the following parts to form a meaningful sentence:
P. technological advancement
Q. has led to
R. in many fields
S. a significant leap
BITSAT - 2025
Sentence Arrangement
View Solution
A dust particle of mass 4 × 10⁻¹² mg is suspended in air under the influence of an electric field of 50 N/C directed vertically upwards. How many electrons were removed from the neutral dust particle? (g = 10 m/s²)
BITSAT - 2025
Electrostatics
View Solution
In a mixture of gases, the average number of degrees of freedom per molecule is 6. If the rms speed of the molecule is \(c\), what is the velocity of sound in the gas?
BITSAT - 2025
kinetic theory
View Solution
View More Questions