Question:

A circular coil of 100 turns has an effective radius of 0.05 m and carries a current of 0.1 A. How much work is required to turn it in an external magnetic field of 1.5 Wb/m\(^2\) through 180° about its axis perpendicular to the magnetic field? The plane of the coil is initially perpendicular to the magnetic field.

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When the coil plane is initially perpendicular to \(B\), the normal is along \(B\) (minimum energy). Rotating 180° brings it to maximum energy: \(W = 2NiAB\).
Updated On: Apr 20, 2026
  • 0.456 J
  • 2.65 J
  • 0.2355 J
  • 3.95 J
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Work done in rotating a magnetic dipole: \(W = U_f - U_i = -MB\cos\theta_f - (-MB\cos\theta_i)\).
Step 2: Detailed Explanation:
Initially, plane is perpendicular to \(B\) \(\Rightarrow\) axis parallel to \(B\): \(\theta_i = 0^\circ\). After rotation: \(\theta_f = 180^\circ\). Work done: \(W = 2NiAB\). Substitute values: \[ W = 2 \times 100 \times 0.1 \times (\pi \times 0.05^2) \times 1.5 = 2 \times 100 \times 0.1 \times 7.85\times10^{-3} \times 1.5 = 0.2355 \text{ J} \]
Step 3: Final Answer:
\[ \boxed{0.2355 \text{ J}} \]
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