Question:
A chloride salt solution acidified with dil $HNO _3$ gives a curdy white precipitate, $[A]$, on addition of $AgNO _3 - [A]$ on treatment with $NH _4 OH$ gives a clear solution, $B$$A$ and $B$ are respectively
A chloride salt solution acidified with dil $HNO _3$ gives a curdy white precipitate, $[A]$, on addition of $AgNO _3 - [A]$ on treatment with $NH _4 OH$ gives a clear solution, $B$$A$ and $B$ are respectively
Updated On: Apr 24, 2025
- $H \left[ AgCl _3\right] \&\left( NH _4\right)\left[ Ag ( OH )_2\right]$
- $H \left[ AgCl _3\right] \&\left[ Ag \left( NH _3\right)_2\right] Cl$
- $AgCl \&\left[ Ag \left( NH _3\right)_2\right] Cl$
- $AgCl \&\left( NH _4\right)\left[ Ag ( OH )_2\right]$
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The Correct Option is C
Approach Solution - 1
Correct answer is (c)
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The precipitate formed when silver chloride (AgCl) is produced is insoluble in water but soluble in ammonia. Ammonia acts as a complexing agent and dissolves AgCl by forming the complex ion [Ag(NH$_3$)$_2$]Cl, which is known as diamminesilver chloride. This complexation occurs because ammonia molecules coordinate with the silver ion, forming a soluble complex.
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