Question

A child of mass 5 kg is going round a merry-goround that makes 1 rotation in 3.14 s. The radius of the merry-go-round is 2 m. The centrifugal force on the child will be

• A. 40 N
• B. 50 N
• C. 80 N
• D. 100 N

Answer 1

The Correct Option is A

Given, \(m = 5 \, \text{kg}\), \(R = 2 \, \text{m}\),

time \(t\) for 1 rev \(= 3.14 \, \text{sec}\) or \(\pi \, \text{sec}\).

So, \(\theta\) for 1 rev \(= 2\pi \, \text{rad}\).

Therefore, \(\omega = \frac{\theta}{t} = \frac{2\pi}{\pi} = 2 \, \text{rad/s}\).

Centrifugal force \(F = mR\omega^2 = 5 \times 2 \times 2^2 = 40 \, \text{N}\).