For magnetic forces on a current-carrying wire, use F = ILB sinθ. Ensure L and B are in consistent units.
The force on a straight conductor in a magnetic field is given by:
\[ F = I L B \sin \theta \]
Here:
Substitute the values:
\[ F = (2)(0.05)(0.75)(1) = 0.075 \, \text{N} \]
The force is given as \(\frac{x}{130} \, \text{N}\). Equating:
\[ \frac{x}{130} = 0.075 \implies x = 0.075 \cdot 130 = 9.75 \]
Thus, the value of \(x\) is 9.

Force on 5cm side is
∣F∣= ILB sinθ
=(2)(5×10−2)×43×1312=1309N
So, x=9
Hence, The correct answer is 9.


A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
The magnetic field is a field created by moving electric charges. It is a force field that exerts a force on materials such as iron when they are placed in its vicinity. Magnetic fields do not require a medium to propagate; they can even propagate in a vacuum. Magnetic field also referred to as a vector field, describes the magnetic influence on moving electric charges, magnetic materials, and electric currents.