Question:
A charge Q is placed at a distance \(a/2\) above the center of the square surface of edge \(a\) as shown in the figure.
The electric flux through the square surface is
A charge Q is placed at a distance \(a/2\) above the center of the square surface of edge \(a\) as shown in the figure.
The electric flux through the square surface is
The electric flux through the square surface is
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Imagine a cube of edge a with the charge at its centre; by symmetry each face gets one sixth of the total flux.
Updated On: Nov 11, 2026
- \(\frac{Q}{\epsilon_0}\)
- \(\frac{Q}{2\epsilon_0}\)
- \(\frac{Q}{3\epsilon_0}\)
- \(\frac{Q}{6\epsilon_0}\)
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The Correct Option is D
Solution and Explanation
The charge is at height a/2 above the centre of the square, so it sits at the centre of a cube of edge a that has this square as one face.
Total flux through the cube: \(\frac{Q}{\epsilon_0}\) (Gauss's law). By symmetry the six faces share it equally.
Flux through the given square = \(\frac{Q}{6\epsilon_0}\).
Answer: (4) \(\frac{Q}{6\epsilon_0}\)
Total flux through the cube: \(\frac{Q}{\epsilon_0}\) (Gauss's law). By symmetry the six faces share it equally.
Flux through the given square = \(\frac{Q}{6\epsilon_0}\).
Answer: (4) \(\frac{Q}{6\epsilon_0}\)
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