Question:
A charge q is located at the centre of a cube. The electric flux through any face is
A charge q is located at the centre of a cube. The electric flux through any face is
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In some formulations, electric flux is expressed using solid angle \(4\pi\) factor.
Updated On: Apr 23, 2026
- \(\frac{q}{6\epsilon_0}\)
- \(\frac{q}{6\pi\epsilon_0}\)
- \(\frac{2\pi q}{6\epsilon_0}\)
- \(\frac{4\pi q}{6\epsilon_0}\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Using Gauss's law in terms of solid angle, total flux associated with a charge can be expressed including angular factor \(4\pi\).
Step 2: Detailed Explanation:
Total flux = \(\frac{4\pi q}{\epsilon_0}\).
Since the cube has 6 faces and symmetry applies, flux through each face = \(\frac{1}{6} \times \frac{4\pi q}{\epsilon_0} = \frac{4\pi q}{6\epsilon_0}\).
Step 3: Final Answer:
Thus, flux through any face = \(\frac{4\pi q}{6\epsilon_0}\).
Using Gauss's law in terms of solid angle, total flux associated with a charge can be expressed including angular factor \(4\pi\).
Step 2: Detailed Explanation:
Total flux = \(\frac{4\pi q}{\epsilon_0}\).
Since the cube has 6 faces and symmetry applies, flux through each face = \(\frac{1}{6} \times \frac{4\pi q}{\epsilon_0} = \frac{4\pi q}{6\epsilon_0}\).
Step 3: Final Answer:
Thus, flux through any face = \(\frac{4\pi q}{6\epsilon_0}\).
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