Question:
A charge of \(2 \times 10^{-2} \, C\) moves at 30 rev/s in a circle of diameter 80 cm. The current linked with the circuit is :
A charge of \(2 \times 10^{-2} \, C\) moves at 30 rev/s in a circle of diameter 80 cm. The current linked with the circuit is :
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Current in circular motion = charge × frequency.
Updated On: Apr 18, 2026
- 0.02 A
- 20 A
- 0.60 A
- 60 A
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
Current:
\[
I = q \times f
\]
Step 1: Given values.
\[ q = 2 \times 10^{-2} \, C, \quad f = 30 \, \text{rev/s} \]
Step 2: Calculate current.
\[ I = qf = 2 \times 10^{-2} \times 30 = 0.6 \, A \]
Step 1: Given values.
\[ q = 2 \times 10^{-2} \, C, \quad f = 30 \, \text{rev/s} \]
Step 2: Calculate current.
\[ I = qf = 2 \times 10^{-2} \times 30 = 0.6 \, A \]
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