Question:

A certain amount of gas is taken through a cyclic process (A B C D A) that has two isobars, one isochore and one isothermal. The cycle can be represented on a \(P-V\) indicator diagram as :

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On a P-V diagram an isobar is a horizontal line, an isochore a vertical line and an isotherm a hyperbola \(PV=\text{const}\) falling with V. The cycle must contain exactly 2 horizontal lines, 1 vertical line and 1 falling curve.
Updated On: Oct 31, 2026
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The Correct Option is C

Solution and Explanation

Identify each process on the P-V plane: isobar = horizontal straight line; isochore = vertical straight line; isotherm = hyperbolic curve with P decreasing as V increases.
The required cycle therefore has two horizontal lines, one vertical line and one hyperbolic arc.
Option (1): two horizontal lines but both side paths are curves, no vertical line. Rejected.
Option (2): all four sides are curves. Rejected. Option (4): no horizontal/vertical straight lines (the sides are slanted or curved). Rejected.
Option (3): AB vertical (isochore), BC horizontal (isobar), CD falling hyperbola (isotherm), DA horizontal (isobar). This matches exactly.
Answer: (3) the diagram of option (3)
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