Step 1: Concept
Velocity is the integral of acceleration, and displacement is the integral of velocity.
Step 2: Meaning
$v = \int 6t dt = 3t^2$. $s = \int 3t^2 dt = t^3$.
Step 3: Analysis
At $t=4$: $v = 3(4^2) = 48 ms^{-1}$. $s = 4^3 = 64 m$.
Step 4: Conclusion
Velocity is 48 and displacement is 64.
Final Answer: (A)