Question:

A car starts from rest with acceleration $a=6t (ms^{-2})$. Its velocity and displacement after 4 seconds are ________.

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$v = \int a dt$ and $s = \int v dt$.
Updated On: Jun 26, 2026
  • 48, 64
  • 16, 24
  • 16, 38
  • 24, 32
  • 32, 24
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The Correct Option is A

Solution and Explanation

Step 1: Concept
Velocity is the integral of acceleration, and displacement is the integral of velocity.

Step 2: Meaning

$v = \int 6t dt = 3t^2$. $s = \int 3t^2 dt = t^3$.

Step 3: Analysis

At $t=4$: $v = 3(4^2) = 48 ms^{-1}$. $s = 4^3 = 64 m$.

Step 4: Conclusion

Velocity is 48 and displacement is 64. Final Answer: (A)
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