0.5
The power factor \( \cos(\phi) \) is given by: \[ \cos(\phi) = \frac{R}{Z} \] where \( Z = \sqrt{R^2 + X_C^2} \). Given \( \frac{X_C}{R} = \frac{4}{3} \), we find: \[ Z = R \sqrt{1 + \left(\frac{4}{3}\right)^2} = R \sqrt{1 + \frac{16}{9}} = R \sqrt{\frac{25}{9}} = \frac{5R}{3} \] Thus, \( \cos(\phi) = \frac{R}{\frac{5R}{3}} = 0.6 \).
The effective capacitance between points A and B shown in the circuit is:
The Wheatstone bridge shown in the diagram is balanced. If P3 is the power dissipated by R3 and P1 is the power dissipated by R1, then the ratio P3/P1 is:
A wire of resistance 2R is stretched such that its length is doubled. Then the increase in its resistance is: