Question:

A boy pushes a box of mass 2 kg with a force \(\vec{F} = (20\hat{i}+10\hat{j})\) N on a frictionless surface. If the box was initially at rest, then ___________ m is displacement along the x-axis after 10s.

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Only the x-component of force affects x-motion: \(a_x = F_x/m\), then \(x = \frac{1}{2}a_xt^2\).
Updated On: Nov 4, 2026
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Correct Answer: 500

Solution and Explanation

\(a_x = \frac{F_x}{m} = \frac{20}{2} = 10\) m/s2.
Starting from rest, \(x = \frac{1}{2}a_xt^2 = \frac{1}{2}\times10\times10^2 = 500\) m.
Answer: 500
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