Question:
A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 m/s, then the KE of the other part is
A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 m/s, then the KE of the other part is
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A bomb of mass 9 kg explodes into two parts. One part of mass 3 kg moves with velocity 16 m/s, then the KE of the other part is
Updated On: Apr 15, 2026
- 162 J
- 150 J
- 192 J
- 200 J
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The Correct Option is C
Solution and Explanation
Step 1: Momentum
Initial momentum = 0. So, $m_1v_1 + m_2v_2 = 0$. $3 \times 16 + 6 \times v = 0 \Rightarrow v = -8 \text{ m/s}$.
Step 2: Kinetic Energy
$KE = \frac{1}{2} m v^2$. $KE = \frac{1}{2} \times 6 \times (8)^2 = 3 \times 64 = 192 \text{ J}$.
Final Answer: (C)
Initial momentum = 0. So, $m_1v_1 + m_2v_2 = 0$. $3 \times 16 + 6 \times v = 0 \Rightarrow v = -8 \text{ m/s}$.
Step 2: Kinetic Energy
$KE = \frac{1}{2} m v^2$. $KE = \frac{1}{2} \times 6 \times (8)^2 = 3 \times 64 = 192 \text{ J}$.
Final Answer: (C)
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