Question:
A body of mass 10 kg is moving with a constant velocity of $10~m/s.$ When a constant force acts for 4 s on it, it moves with a velocity $2~m/s$ in the opposite direction. The acceleration produced in it is
A body of mass 10 kg is moving with a constant velocity of $10~m/s.$ When a constant force acts for 4 s on it, it moves with a velocity $2~m/s$ in the opposite direction. The acceleration produced in it is
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A body of mass 10 kg is moving with a constant velocity of $10~m/s.$ When a constant force acts for 4 s on it, it moves with a velocity $2~m/s$ in the opposite direction. The acceleration produced in it is
Updated On: Apr 15, 2026
- $3~m/s^{2}$
- $-3~m/s^{2}$
- $0.3~m/s^{2}$
- $0.03~m/s^{2}$
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The Correct Option is B
Solution and Explanation
Step 1: Formula
Use the first equation of motion: $v = u + at$.
Step 2: Values
Initial velocity $u = 10 \text{ m/s}$. Final velocity $v = -2 \text{ m/s}$ (opposite direction). Time $t = 4 \text{ s}$.
Step 3: Calculation
$-2 = 10 + a \times 4$. $4a = -12 \Rightarrow a = -3 \text{ m/s}^{2}$.
Final Answer: (B)
Use the first equation of motion: $v = u + at$.
Step 2: Values
Initial velocity $u = 10 \text{ m/s}$. Final velocity $v = -2 \text{ m/s}$ (opposite direction). Time $t = 4 \text{ s}$.
Step 3: Calculation
$-2 = 10 + a \times 4$. $4a = -12 \Rightarrow a = -3 \text{ m/s}^{2}$.
Final Answer: (B)
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