Question:
A body of mass \( 0.2\,\text{kg} \) travels along a straight line with velocity \( v = (2x^2 + 2)\,\text{m s}^{-1} \). The net work done by the driving force during its displacement from \( x = 0 \) to \( x = 2 \,\text{m} \) is
A body of mass \( 0.2\,\text{kg} \) travels along a straight line with velocity \( v = (2x^2 + 2)\,\text{m s}^{-1} \). The net work done by the driving force during its displacement from \( x = 0 \) to \( x = 2 \,\text{m} \) is
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Always use kinetic energy change for work in variable velocity problems.
Updated On: Apr 21, 2026
- \(2\,\text{J} \)
- \(5.4\,\text{J} \)
- \(9.6\,\text{J} \)
- \(10.8\,\text{J} \)
- \(6.5\,\text{J} \)
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The Correct Option is C
Solution and Explanation
Concept:
Work-energy theorem:
\[
W = \frac{1}{2}m(v^2 - u^2)
\]
Step 1: Find velocities.
\[ v(0)=2,\quad v(2)=10 \]
Step 2: Apply formula.
\[ W = \frac{1}{2}\cdot 0.2 (100 - 4) = 0.1 \cdot 96 = 9.6 \]
Step 1: Find velocities.
\[ v(0)=2,\quad v(2)=10 \]
Step 2: Apply formula.
\[ W = \frac{1}{2}\cdot 0.2 (100 - 4) = 0.1 \cdot 96 = 9.6 \]
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