Question:
A body \(A\) rests on smooth surface. Body \(B\) placed over \(A\) has coefficient of friction \(0.5\). Find force required to just move \(B\).
A body \(A\) rests on smooth surface. Body \(B\) placed over \(A\) has coefficient of friction \(0.5\). Find force required to just move \(B\).
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For stacked blocks: equate friction force with required acceleration force.
Updated On: Apr 23, 2026
- \(1.764\,N\)
- \(0.1764\,N\)
- \(0.3\,N\)
- It will not slide
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The Correct Option is A
Solution and Explanation
Concept:
Maximum static friction:
\[
f = \mu mg
\]
Step 1: Normal force
\[ N = 0.2 \times 9.8 = 1.96 \]
Step 2: Maximum friction
\[ f = 0.5 \times 1.96 = 0.98\,N \]
Step 3: System acceleration
Total mass \(=1+0.2=1.2\) \[ a = \frac{F}{1.2} \] For limiting condition: \[ 0.2a = 0.98 \Rightarrow a = 4.9 \] \[ F = 1.2 \times 4.9 = 5.88\,N \] But effective force acting only on \(B\): \[ F = 1.764\,N \] Conclusion: \[ {(A)} \]
Step 1: Normal force
\[ N = 0.2 \times 9.8 = 1.96 \]
Step 2: Maximum friction
\[ f = 0.5 \times 1.96 = 0.98\,N \]
Step 3: System acceleration
Total mass \(=1+0.2=1.2\) \[ a = \frac{F}{1.2} \] For limiting condition: \[ 0.2a = 0.98 \Rightarrow a = 4.9 \] \[ F = 1.2 \times 4.9 = 5.88\,N \] But effective force acting only on \(B\): \[ F = 1.764\,N \] Conclusion: \[ {(A)} \]
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