Question:
A block of mass $10~\text{kg}$ moving with a speed of $5~\text{m/s}$ on a frictionless horizontal surface suddenly explodes into two pieces.
If one piece with mass $4~\text{kg}$ moves with a speed of $10~\text{m/s}$, then the velocity of the second piece is
A block of mass $10~\text{kg}$ moving with a speed of $5~\text{m/s}$ on a frictionless horizontal surface suddenly explodes into two pieces.
If one piece with mass $4~\text{kg}$ moves with a speed of $10~\text{m/s}$, then the velocity of the second piece is
If one piece with mass $4~\text{kg}$ moves with a speed of $10~\text{m/s}$, then the velocity of the second piece is
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Use momentum conservation when no external force acts. Total momentum before = after.
Updated On: Jan 2, 2026
- $7.67~\text{m/s}$
- $1.67~\text{m/s}$
- $6.67~\text{m/s}$
- $2.67~\text{m/s}$
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The Correct Option is B
Solution and Explanation
Initial momentum $= 10 \cdot 5 = 50~\text{kg m/s}$
Let second piece have mass $6~\text{kg}$ and velocity $v$
After explosion: $4 \cdot 10 + 6 \cdot v = 50$
$40 + 6v = 50 \Rightarrow 6v = 10 \Rightarrow v = \dfrac{10}{6} = 1.67~\text{m/s}$
Let second piece have mass $6~\text{kg}$ and velocity $v$
After explosion: $4 \cdot 10 + 6 \cdot v = 50$
$40 + 6v = 50 \Rightarrow 6v = 10 \Rightarrow v = \dfrac{10}{6} = 1.67~\text{m/s}$
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