
Given:
A battery of emf \( E \) and internal resistance \( r \) is connected in series with an external resistance \( R \).
Concept:
The voltage across the external resistance \( R \) is given by: \[ V = E - Ir \] where \( I = \frac{E}{R + r} \) So the voltage across \( R \) becomes: \[ V = E - \left( \frac{E}{R + r} \right) r = \frac{E R}{R + r} \]
For the battery to act as a constant voltage source:
The voltage across the external resistance \( V \approx E \). This happens when the drop across internal resistance is negligible. \[ \text{This implies } r \ll R \]
Therefore, the battery will act as a constant voltage source when:
r << R

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