Question:

A battery of emf 10 V is connected to resistance as shown in figure. The potential difference $VA-VB$ between the points A and B is

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A battery of emf 10 V is connected to resistance as shown in figure. The potential difference $VA-VB$ between the points A and B is \includegraphics[width=0.5\linewidth]7phy.png \labelfig:placeholder
Updated On: Apr 15, 2026
  • -2 V
  • 2 V
  • 5 V
  • $\frac{20}{11} V$
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The Correct Option is B

Solution and Explanation

Step 1: Calculation
Total resistance $R_{eq}=5\Omega$. Total current $i = \frac{10}{5} = 2 A$. Current in each branch is $1 A$.
Step 2: Node Potentials
$V_{C} - V_{A} = 1 \times 1 = 1 V$. $V_{C} - V_{B} = 1 \times 3 = 3 V$.
Step 3: Final Step
Subtracting the equations gives $V_{A} - V_{B} = 2 V$.
Final Answer: (B)
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