Step 1: Identify B as the Don School student described in the clues.
A, B and C are the three Don School students. The unnamed student who is brighter than A and also brighter than C cannot be A or C, since neither can be brighter than themselves. So this student is B.
Step 2: List the comparisons that involve P, Q and R.
The clues give P is brighter than B, B is brighter than Q, and separately Q is brighter than R.
Step 3: Connect P, Q and R directly.
Since P is brighter than B and B is brighter than Q, it follows that P is brighter than Q. Combined with the direct clue Q is brighter than R, the order among the three Elite School students becomes P, then Q, then R.
Step 4: Read off the dullest of the three.
In the order P, Q, R, R sits at the bottom of this group, meaning R is duller than both P and Q.
Step 5: Verify against the options.
P cannot be the dullest since it is shown to be the brightest of the three. Q cannot be the dullest since Q is brighter than R. Cannot be decided does not apply because the clues fully fix the order P, Q, R. Therefore R is the dullest among the three Elite School students.