To determine the volume of distribution (\(V_d\)) of a drug, we use the relationship between the dose administered, the plasma concentration, and the volume of distribution. The formula for calculating the volume of distribution is:
\(V_d = \frac{Dose}{C_0}\)
Where:
In the given problem:
Substituting these values into the formula, we get:
\(V_d = \frac{1000}{50} = 20 \, \text{L}\)
Thus, the volume of distribution of the drug is 20 liters. This means that the initial drug concentration was evenly distributed in a volume of 20 liters in the body.
Conclusion: The correct answer is 20L.
This calculation helps in understanding how extensively a drug disperses into body tissues compared to the blood. A larger volume of distribution indicates more extensive distribution into tissues.
Decrease in effective surface area available to the dissolution medium leading to a fall in the dissolution rate, may happen due to which one of the following reasons?
| List I | List II | ||
| A | When two dosage forms have equal t max | I | When their total body clearance is constant. |
| B | AUC values of the two analogs can be compared to measure relative bioavailability | II | Absorption rate constants are equal |
| C | Urinary data is valid to measure bioavailability. III. W | III | When fraction absorbed and elimination rate is constant. |
| D | C max is proportional to the rate of absorption | IV | Excretion of drug and/or metabolite is related to the bioavailable dose. |
Choose the correct answer from the options given below:
List I | List II | ||
|---|---|---|---|
| A | \(\Omega^{-1}\) | I | Specific conductance |
| B | \(∧\) | II | Electrical conductance |
| C | k | III | Specific resistance |
| D | \(\rho\) | IV | Equivalent conductance |
List I | List II | ||
|---|---|---|---|
| A | Constant heat (q = 0) | I | Isothermal |
| B | Reversible process at constant temperature (dT = 0) | II | Isometric |
| C | Constant volume (dV = 0) | III | Adiabatic |
| D | Constant pressure (dP = 0) | IV | Isobar |