Question:

A 2V battery is connected across AB as shown in the figure. The value of the current supplied by the battery when in one case battery's positive terminal is connected to A and in other case when positive terminal of battery is connected to B will respectively be :

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Only one diode conducts in each polarity: with A positive, D1 conducts through 5 ohm; with B positive, D2 conducts through 10 ohm. Use I = V/R for each case (ideal diodes).
Updated On: Nov 11, 2026
  • 0.2 A and 0.1 A
  • 0.4 A and 0.2 A
  • 0.1 A and 0.2 A
  • 0.2 A and 0.4 A
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The Correct Option is B

Solution and Explanation

Assume ideal diodes (zero forward resistance, infinite reverse resistance). In the figure, D1 is in series with the 5 \(\Omega\) resistor in the upper branch (conducting from left to right), and D2 is in series with the 10 \(\Omega\) resistor in the lower branch (conducting from right to left). The two branches are in parallel between the left and right nodes, which connect to A and B respectively.
Case 1: positive terminal at A. The left node is at higher potential, so D1 is forward biased and D2 is reverse biased. Only the 5 \(\Omega\) branch conducts: \(I = \frac{2}{5} = 0.4\) A.
Case 2: positive terminal at B. The right node is at higher potential, so D2 is forward biased and D1 reverse biased. Only the 10 \(\Omega\) branch conducts: \(I = \frac{2}{10} = 0.2\) A.
Answer: (2) 0.4 A and 0.2 A
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