Question:
In the given figure, each diode has a forward bias resistance of \(30\,\Omega\) and infinite resistance in reverse bias. The current \(I_1\) will be :
In the given figure, each diode has a forward bias resistance of \(30\,\Omega\) and infinite resistance in reverse bias. The current \(I_1\) will be :
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Decide which diodes conduct from the battery polarity; only forward-biased branches carry current, each with \(130 + 30 = 160\,\Omega\).
Updated On: Nov 4, 2026
- 3.75 A
- 2.35 A
- 2 A
- 2.73 A
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The Correct Option is C
Solution and Explanation
The positive plate (longer line) of the 200 V battery is connected to the left wire, so conventional current flows from the left wire towards the right through the branches. The upper two diodes point to the right, so they are forward biased; the third diode points to the left, so it is reverse biased and its branch carries no current.
Each conducting branch: \(130 + 30 = 160\,\Omega\). Two such branches in parallel: \(\frac{160}{2} = 80\,\Omega\).
In series with the \(20\,\Omega\) resistor: \(R_{total} = 80 + 20 = 100\,\Omega\).
\(I_1 = \frac{200}{100} = 2\) A.
Answer: (3) 2 A
Each conducting branch: \(130 + 30 = 160\,\Omega\). Two such branches in parallel: \(\frac{160}{2} = 80\,\Omega\).
In series with the \(20\,\Omega\) resistor: \(R_{total} = 80 + 20 = 100\,\Omega\).
\(I_1 = \frac{200}{100} = 2\) A.
Answer: (3) 2 A
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